(4c^2)+4c+1=0

Solution for (4c^2)+4c+1=0 equation:

Simplifying
(4c2) + 4c + 1 = 0

Reorder the terms:
1 + 4c + (4c2) = 0

Solving
1 + 4c + (4c2) = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + 2c)(1 + 2c) = 0

Subproblem 1
Set the factor '(1 + 2c)' equal to zero and attempt to solve:

Simplifying
1 + 2c = 0

Solving
1 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2c = 0 + -1
2c = 0 + -1

Combine like terms: 0 + -1 = -1
2c = -1

Divide each side by '2'.
c = -0.5

Simplifying
c = -0.5
Subproblem 2
Set the factor '(1 + 2c)' equal to zero and attempt to solve:

Simplifying
1 + 2c = 0

Solving
1 + 2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2c = 0 + -1
2c = 0 + -1

Combine like terms: 0 + -1 = -1
2c = -1

Divide each side by '2'.
c = -0.5

Simplifying
c = -0.5
Solution
c = {-0.5, -0.5}